c# - Display Pop up Window -

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in requirement have 1 dropdown , 2 buttons. • select config file - dropdown • create new • view config file - button • modify config file - button here select config file drop down.if user clicks drop down "create new" option come. if user clicks "create new", pop window should come. here code pop window under modelpopup.aspx, 

              <asp:gridview id="gridview1" runat="server"></asp:gridview>               <asp:button id="addrowbtn" runat="server" text="add new row" />               <asp:button id="savenewbtn" runat="server" text="save new" />               <asp:button id="savebtn" runat="server" text="save" />       </div>     </div>          <script type="text/javascript">         $(function () {             $("[id*=btnvcf]").click(function () {                 showpopup();                 return false;             });         });         function showpopup() {             $("#popup").dialog({                 title: "gridview",                 width: 450,                 buttons: {                     ok: function () {                         $(this).dialog('close');                     }                 },                 modal: true             });         }     </script>     </form>

is code correct. how can display popup code.


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