sql - Finding top 3 IDs with the largest count, by group - is it possible to avoid a triple nested query? -

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i need find top 3 'userids' 'time' in terms of count in 'table'. example of input , output:

table

id    userid    time 1              '1' 2              '1' 3       b        '2' 4       b        '4' 5       b        '4' etc

desired result:

time    userid    number    rank  '1'              17       1  '1'      c         11       2  '1'      q         9        3  '2'      b         13       1  '2'      c         9        2  '2'      m         7        3 etc

i've been able accomplish using triple query there way simplify?

select userid, number, time, rank (  select userid, number, time, rank() on (partition time order number desc) rank   (select count(distinct(id)) number,  userid,  time table group 2, 3)  )  rank <= 3

i'm wondering if 'having' clause applicable here, since seems slow otherwise.

are happy this?

;with cte_ranking ( select time, userid, count(time) number, rank() on (partition time order count(time) desc) rank table group time,userid )  select * cte_ranking rank < 3 order time

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