c - linked list print function is not working -

this program runs without error doesn't print anything. couldn't figure out error.

i'm learning data structure in c, practice learn data structure?

thanks in advance!!!!!!

#include<stdio.h> #include<stdlib.h>   typedef struct node  {    int data;    struct node *next;  }list_node;    list_node* push(list_node* head_r, int new_data)  {     list_node* new_node = (list_node*)malloc(sizeof(list_node));      new_node->data  = new_data;     new_node->next = head_r;     head_r = new_node;     return head_r;   }  void print(list_node* head_r)    {    while(head_r)     {       printf("%d\n", head_r->data);       head_r = head_r->next;     }    }   int main()  {      list_node* l_list = null;   push(l_list, 1);   push(l_list, 2);   push(l_list, 6);   push(l_list, 8);   push(l_list, 7);   push(l_list, 3);   push(l_list, 4);    printf("given linked list \n");   print(l_list);    return 0;  } 

your list empty because push returned value not used

your main should this:

int main()  {      list_node* l_list = null;   l_list = push(l_list, 1);   l_list = push(l_list, 2);   l_list = push(l_list, 6);   l_list = push(l_list, 8);   l_list = push(l_list, 7);   l_list = push(l_list, 3);   l_list = push(l_list, 4);    printf("given linked list \n");   print(l_list);    return 0;  } 

or can pass list reference , time code this:

void push(list_node** head_r, int new_data)  {     list_node* new_node = (list_node*)malloc(sizeof(list_node));      new_node->data  = new_data;     new_node->next = *head_r;     *head_r = new_node;   }  int main()  {      list_node* l_list = null;   push(&l_list, 1);   push(&l_list, 2);   push(&l_list, 6);   push(&l_list, 8);   push(&l_list, 7);   push(&l_list, 3);   push(&l_list, 4);    printf("given linked list \n");   print(l_list);    return 0;  }