php - How to fix: Warning: mysqli_get_server_info() expects parameter 1 to be mysqli? -

i'm bad in php , i'm trying install arfoo.com on host. had problem mysql , mysqli, fixed now.

but error:

warning: mysqli_get_server_info() expects parameter 1 mysqli, string given in /home/***/install/step4.php on line 47

for following code:

<?php /**  * arfooo  *   * @package    arfooo  * @copyright  copyright (c) arfooo annuaire (fr) , arfooo directory (en)  *             guillaume hocine (c) 2007 - 2010  *             http://www.arfooo.com/ (fr) , http://www.arfooo.net/ (en)  * @author     guillaume hocine & adrian galewski  * @license    http://creativecommons.org/licenses/by/2.0/fr/ creative commons  */ session_start(); error_reporting(e_all); require_once('languages/' . $_session['selectedlanguage'] . '.php');   $chemin_includes_header = 'includes/'; include_once($chemin_includes_header.'header.php');   require_once("dbfunctions.php");  require_once("createdb.php");  function createdbconfig($dbhost, $dbuser, $dbpass, $dbname, $dbprefix) {     $dbconfig['db_host'] = $dbhost;     $dbconfig['db_user'] = $dbuser;     $dbconfig['db_pass'] = $dbpass;     $dbconfig['db_name'] = $dbname;     $dbconfig['db_prefix'] = $dbprefix;     $dbconfig['db_installed'] = true;      $data = "<?php\n \$dbconfig = " . var_export($dbconfig, true). ";\n ?>";     file_put_contents("../config/db.php", $data); }  $_session['mysqlserver'] = $_post['mysqlserver']; $_session['mysqluser'] = $_post['mysqluser']; $_session['mysqlpassword'] = $_post['mysqlpassword']; $_session['mysqldatabasename'] = $_post['mysqldatabasename']; $_session['mysqltablesprefix'] = $_post['mysqltablesprefix'];  dbconnect($_session['mysqlserver'],           $_session['mysqluser'],           $_session['mysqlpassword'],           $_session['mysqldatabasename']           );  $mysqlversion = mysqli_get_server_info();      $mysqlversioncorrect = version_compare($mysqlversion, "4.1", ">=");  if($mysqlversioncorrect) {      createdbconfig($_post['mysqlserver'],                    $_post['mysqluser'],                    $_post['mysqlpassword'],                    $_post['mysqldatabasename'],                    $_post['mysqltablesprefix']);        $tableslist = createdbtables($_post['mysqltablesprefix'],                                  $_session['siterooturl'],                                  $_session['selectedlanguage'],                                  $_session['urlrewriting']                                  ); } else {     $tableslist = array(); }  ?> 

edit:

function dbconnect($server, $user, $pass, $dbname) {      /* install database prefixed tables */      $conn = mysqli_connect($server, $user, $pass, $dbname);     //mysql_connect($server, $user, $pass) or die('could not connect mysql');;      mysqli_query($conn, 'create temporary table table');     //mysqli_query($dbname, 'create temporary table `table`');     //mysql_query('create database if not exists ' . $dbname);      mysqli_select_db($conn, $dbname) or die('could not select database'); } 

any kind highly appreciated!

you should pass object returned mysqli_connect() argument mysqli_get_server_info() if want use procedural style.

$mysqlconnect = mysqli_connect("localhost", "my_user", "my_password"); $mysqlversion = mysqli_get_server_info($mysqlconnect);     

or using oo style :

$mysqlconnect = new mysqli("localhost", "my_user", "my_password"); $mysqlversion = $mysqlconnect->server_info; 

see more @ http://php.net/mysqli_get_server_info

edit :

your dbconnect() function should return mysqli object, try add return $conn; @ end, :

function dbconnect($server, $user, $pass, $dbname) {      /* install database prefixed tables */      $conn = mysqli_connect($server, $user, $pass, $dbname);     //mysql_connect($server, $user, $pass) or die('could not connect mysql');;      mysqli_query($conn, 'create temporary table table');     //mysqli_query($dbname, 'create temporary table `table`');     //mysql_query('create database if not exists ' . $dbname);      mysqli_select_db($conn, $dbname) or die('could not select database');      return $conn; }