How can I replace a number of list elements between 2 boundary symbols in a python list -

given list of zeros , boundary elements (ones) there efficient way replace zeros, if less n of them appear between ones?

for n=3: [1,0,0,1,1,1,0,0,0,1,0,0,0] => [1,1,1,1,1,1,0,0,0,1,0,0,0] 

some more cases:

[1,0,0,1] => [1,1,1,1]  [0,0,1] => [0,0,1]  [1,0,0] => [1,0,0] 

you can convert list str , use replace method, convert list:

data = [1, 0, 0, 1, 1, 1, 0, 0, 0, 1, 0, 0, 0] n = 3  repl = (("1" + "0" * + "1", "1" + "1" * + "1") in range(1, n)) data_str = "".join(str(i) in data) r in repl: while true:     new_str = data_str.replace(r[0], r[1])     if new_str == data_str:         break     else:         data_str = new_str new_data = list(int(s) s in data_str) print(new_data) 

this print

[1, 1, 1, 1, 1, 1, 0, 0, 0, 1, 0, 0, 0] 

it looks little convoluted works fine if have small lists not cause memory issues.