java - Connect QPushButton Jambi -

i'm pretty new java programming. wrote application listed below, can't connect button function. idea i'm doing wrong?

package com.teat; import com.trolltech.qt.gui.*;  public class application  {      public static void main(string[] args)      {         qapplication.initialize(args);         qwidget mainwidget = new qwidget();         mainwidget.setwindowtitle("simple example");         qhboxlayout main_layout = new qhboxlayout();         mainwidget.setlayout(main_layout);          qpushbutton new_action = new qpushbutton("working");         new_action.released.connect("tata()");         main_layout.addwidget(new_action);          sumnum(5,3);         mainwidget.show();         qapplication.execstatic();         qapplication.shutdown();     }      private static int sumnum(int num1,int num2)     {         int sum = num1 + num2;         system.out.println(sum);         return sum;      }     private static void tata(){         system.out.println("yes, it's working");     }  } 

when call function sumnum(5,3); works perfectly, when call button, don't work. i'm using new_action.released.connect("tata()");

i've looked qt, it's giving me
void com.trolltech.qt.qsignalemitter.abstractsignal.connect(object receiver, string method) object receiver?

i give object receiver, new_action.released.connect(new_action,"tata()"); but, nope, didn't work either.

any idea?

edit: here same application in python:

import sys pyqt4 import qtgui, qtcore  class example(qtgui.qwidget):      def __init__(self):         super(example, self).__init__()         self.setwindowtitle('simple example')          main_layout = qtgui.qhboxlayout()         self.setlayout(main_layout)          new_action = qtgui.qpushbutton("working")         new_action.released.connect(self.tata)         main_layout.addwidget(new_action)          self.show()      def sumnum(self, num1, num2):         print num1+num2         return num1+num2      def tata(self):         print "yes, it's working"   def main():     app = qtgui.qapplication(sys.argv)     ex = example()     sys.exit(app.exec_())   if __name__ == '__main__':     main() 

in python didn't ask object receiver, , it's run it, in java seems different.

as smar said, needed run in loop, extend qwidget, initial settings in application(), setup layout in initui() , run in main().

import com.trolltech.qt.core.*; import com.trolltech.qt.gui.*;  public class application extends qwidget {      public application() {          setwindowtitle("simple example");         setminimumheight(100);         setminimumwidth(100);         setgeometry(250, 250, 350, 100);          initui();          show();     }      private void initui() {          qhboxlayout main_layout = new qhboxlayout(this);          qpushbutton new_action = new qpushbutton("working");         new_action.released.connect(this,"tata()");         main_layout.addwidget(new_action);      }      private void tata(){         system.out.println("yes, it's working");     }      public static void main(string[] args) {         qapplication.initialize(args);         new application();         qapplication.execstatic();         qapplication.shutdown();     } } 

since extended qwidget, need set layout qhboxlayout main_layout = new qhboxlayout(this); notice this
connecting button new_action.released.connect(this,"tata()"); object receiver or in word current qwidget

it's same python, python use self , java use this.

that's worked me, hope having same problem.