Declaring arrays in c language without initial size -

write program manipulate temperature details given below.
- input number of days calculated. – main function
- input temperature in celsius – input function
- convert temperature celsius fahrenheit.- separate function
- find average temperature in fahrenheit.

how can make program without initial size of array ??

#include<stdio.h> #include<conio.h> void input(int); int temp[10]; int d; void main() {     int x=0;     float avg=0,t=0;     printf("\nhow many days : ");     scanf("%d",&d);     input(d);     conv();     for(x=0;x<d;x++)     {         t=t+temp[x];     }     avg=t/d;     printf("avarage %f",avg);     getch(); } void input(int d) {     int x=0;     for(x=0;x<d;x++)     {         printf("input temperature in celsius #%d day",x+1);         scanf("%d",&temp[x]);     } } void conv() {     int x=0;     for(x=0;x<d;x++)     {         temp[x]=1.8*temp[x]+32;     } } 

in c arrays , pointers closely related. in fact, design array syntax convention accessing pointer allocated memory.

so in c statement

 anyarray[n]  

is same as

 *(anyarray+n) 

using pointer arithmetic.

you don't have worry details make "work" designed intuitive.

just create pointer, , allocate memory , access array.

here examples --

int *temp = null; // our array   // allocate space 10 items temp = malloc(sizeof(int)*10);   // reference first element of temp temp[0] = 70;   // free memory when done free(temp); 

remember -- if access outside of allocated area have unknown effects.